发布于 2016-07-19 08:38:33 | 187 次阅读 | 评论: 0 | 来源: 网友投递

这里有新鲜出炉的Java函数式编程,程序狗速度看过来!

Java程序设计语言

java 是一种可以撰写跨平台应用软件的面向对象的程序设计语言,是由Sun Microsystems公司于1995年5月推出的Java程序设计语言和Java平台(即JavaEE(j2ee), JavaME(j2me), JavaSE(j2se))的总称。


这篇文章主要介绍了java实现递归文件列表的方法,实例分析了java采用递归算法遍历文件的技巧,具有一定参考借鉴价值,需要的朋友可以参考下

本文实例讲述了java实现递归文件列表的方法。分享给大家供大家参考。具体如下:

FileListing.java如下:


import java.util.*;
import java.io.*;
/**
* Recursive file listing under a specified directory.
* 
* @author javapractices.com
* @author Alex Wong
* @author anonymous user
*/
public final class FileListing {
 /**
 * Demonstrate use.
 * 
 * @param aArgs - <tt>aArgs[0]</tt> is the full name of an existing 
 * directory that can be read.
 */
 public static void main(String... aArgs) throws FileNotFoundException {
  File startingDirectory= new File(aArgs[0]);
  List<File> files = FileListing.getFileListing(startingDirectory);
  //print out all file names, in the the order of File.compareTo()
  for(File file : files ){
   System.out.println(file);
  }
 }
 /**
 * Recursively walk a directory tree and return a List of all
 * Files found; the List is sorted using File.compareTo().
 *
 * @param aStartingDir is a valid directory, which can be read.
 */
 static public List<File> getFileListing(
  File aStartingDir
 ) throws FileNotFoundException {
  validateDirectory(aStartingDir);
  List<File> result = getFileListingNoSort(aStartingDir);
  Collections.sort(result);
  return result;
 }
 // PRIVATE //
 static private List<File> getFileListingNoSort(
  File aStartingDir
 ) throws FileNotFoundException {
  List<File> result = new ArrayList<File>();
  File[] filesAndDirs = aStartingDir.listFiles();
  List<File> filesDirs = Arrays.asList(filesAndDirs);
  for(File file : filesDirs) {
   result.add(file); //always add, even if directory
   if ( ! file.isFile() ) {
    //must be a directory
    //recursive call!
    List<File> deeperList = getFileListingNoSort(file);
    result.addAll(deeperList);
   }
  }
  return result;
 }
 /**
 * Directory is valid if it exists, does not represent a file, and can be read.
 */
 static private void validateDirectory (
  File aDirectory
 ) throws FileNotFoundException {
  if (aDirectory == null) {
   throw new IllegalArgumentException("Directory should not be null.");
  }
  if (!aDirectory.exists()) {
   throw new FileNotFoundException("Directory does not exist: " + aDirectory);
  }
  if (!aDirectory.isDirectory()) {
   throw new IllegalArgumentException("Is not a directory: " + aDirectory);
  }
  if (!aDirectory.canRead()) {
   throw new IllegalArgumentException("Directory cannot be read: " + aDirectory);
  }
 }
}

希望本文所述对大家的java程序设计有所帮助。



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