发布于 2016-03-23 13:24:03 | 188 次阅读 | 评论: 0 | 来源: 网友投递

这里有新鲜出炉的精品教程,程序狗速度看过来!

Oracle关系数据库管理系统

Oracle Database,又名Oracle RDBMS,或简称Oracle。是甲骨文公司的一款关系数据库管理系统。到目前仍在数据库市场上占有主要份额。


这篇文章主要介绍了Oracle中检查外键是否有索引的SQL脚本分享,本文给出了两个版本的脚本源码,一个查询所有用户,一个查询单用户,需要的朋友可以参考下



COLUMN COLUMNS format a30 word_wrapped 

COLUMN tablename format a15 word_wrapped 

COLUMN constraint_name format a15 word_wrapped 

SELECT TABLE_NAME, 

       CONSTRAINT_NAME, 

       CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) || 

       NVL2(CNAME3, ',' || CNAME3, NULL) || 

       NVL2(CNAME4, ',' || CNAME4, NULL) || 

       NVL2(CNAME5, ',' || CNAME5, NULL) || 

       NVL2(CNAME6, ',' || CNAME6, NULL) || 

       NVL2(CNAME7, ',' || CNAME7, NULL) || 

       NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS 

  FROM (SELECT B.TABLE_NAME, 

               B.CONSTRAINT_NAME, 

               MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1, 

               MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2, 

               MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3, 

               MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4, 

               MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5, 

               MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6, 

               MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7, 

               MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8, 

               COUNT(*) COL_CNT 

          FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME, 

                       SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME, 

                       SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME, 

                       POSITION 

                  FROM USER_CONS_COLUMNS) A, 

               USER_CONSTRAINTS B 

         WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME 

           AND B.CONSTRAINT_TYPE = 'R' 

         GROUP BY B.TABLE_NAME, B.CONSTRAINT_NAME) CONS 

 WHERE COL_CNT > ALL 

 (SELECT COUNT(*) 

          FROM USER_IND_COLUMNS I 

         WHERE I.TABLE_NAME = CONS.TABLE_NAME 

           AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5, 

                CNAME6, CNAME7, CNAME8) 

           AND I.COLUMN_POSITION <= CONS.COL_CNT 

         GROUP BY I.INDEX_NAME) 

/


在上面的基础上修改了一下,可以检查所有的用户。


SET linesize 400;

COLUMN OWNER format a10 word_wrapped 

COLUMN COLUMNS format a30 word_wrapped 

COLUMN TABLE_NAME format a15 word_wrapped 

COLUMN CONSTRAINT_NAME format a40 word_wrapped 

SELECT OWNER,

     TABLE_NAME, 

       CONSTRAINT_NAME, 

       CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) || 

       NVL2(CNAME3, ',' || CNAME3, NULL) || 

       NVL2(CNAME4, ',' || CNAME4, NULL) || 

       NVL2(CNAME5, ',' || CNAME5, NULL) || 

       NVL2(CNAME6, ',' || CNAME6, NULL) || 

       NVL2(CNAME7, ',' || CNAME7, NULL) || 

       NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS 

  FROM (SELECT B.OWNER,B.TABLE_NAME, 

               B.CONSTRAINT_NAME, 

               MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1, 

               MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2, 

               MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3, 

               MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4, 

               MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5, 

               MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6, 

               MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7, 

               MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8, 

               COUNT(*) COL_CNT 

          FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME, 

                       SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME, 

                       SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME, 

                       POSITION 

                  FROM DBA_CONS_COLUMNS WHERE OWNER NOT IN ('SYS','SYSTEM','SYSMAN','HR','OE','EXFSYS','DBSNMP','MDSYS','OLAPSYS','SCOTT','EXFSYS','SH','PM','CTXSYS')) A, 

               DBA_CONSTRAINTS B 

         WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME 

           AND B.CONSTRAINT_TYPE = 'R' 

         GROUP BY B.OWNER,B.TABLE_NAME, B.CONSTRAINT_NAME) CONS 

 WHERE COL_CNT > ALL 

 (SELECT COUNT(*) 

          FROM DBA_IND_COLUMNS I 

         WHERE I.TABLE_NAME = CONS.TABLE_NAME AND I.TABLE_OWNER=CONS.OWNER

           AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5, 

                CNAME6, CNAME7, CNAME8) 

           AND I.COLUMN_POSITION <= CONS.COL_CNT 

         GROUP BY I.INDEX_NAME) 

/



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