发布于 2015-02-14 07:56:58 | 223 次阅读 | 评论: 0 | 来源: 网友投递
这里有新鲜出炉的Python3 官方中文指南,程序狗速度看过来!
Python编程语言
Python 是一种面向对象、解释型计算机程序设计语言,由Guido van Rossum于1989年底发明,第一个公开发行版发行于1991年。Python语法简洁而清晰,具有丰富和强大的类库。它常被昵称为胶水语言,它能够把用其他语言制作的各种模块(尤其是C/C++)很轻松地联结在一起。
本文为大家提供的是一个python实现的文件夹清理程序示例代码,可以按时间清理和指定配置文件清理,很实用,需要的朋友可以参考下
使用:
表示对c:test目录只保留最近10天的子文件夹和keepfile.txt中指定的子文件夹。
代码:
def preCheckDir(dir):
if(not os.path.exists(dir)):
print("error: the directory your input is not existed")
return
if(not os.path.isdir(dir)):
print ("error: the parameter your input is not a directory")
return
return os.path.abspath(dir)
def isKeepByDay(dir, day):
indays = False
if( day is not None) :
t = os.path.getctime(dir)
today = datetime.date.today()
createdate = datetime.date.fromtimestamp(t)
indate = today - datetime.timedelta(days = int(day))
print (createdate)
if(createdate >= indate):
indays = True
print (indays)
return indays
def isKeepByKeepfile(dir, keepfile):
needkeep = False
print (dir)
if (keepfile is not None):
try :
kf = open(keepfile,"r")
for f in kf.readlines():
print (f)
if (dir.upper().endswith("\" + f.strip().upper())):
needkeep = True
kf.close()
except:
print ("error: keep file cannot be opened")
print(needkeep)
return needkeep
def removeSubFolders(dir, day, keepfile):
subdirs = os.listdir(dir)
for subdir in subdirs:
subdir = os.path.join(dir,subdir)
if ( not os.path.isdir(subdir)):
continue
print("----------------------")
if( (not isKeepByDay(subdir, day))and (not isKeepByKeepfile(subdir, keepfile))):
print("remove subfolder: " + subdir)
import shutil
shutil.rmtree(subdir,True)
def FolderCleanUp():
(day, keepfile, dir) = getOption()
dir = preCheckDir(dir)
if dir is None:
return
removeSubFolders(dir,day,keepfile)
if __name__=='__main__':
FolderCleanUp()
对目录下保留最后的zip文件:
zipfiles = [os.path.join(zipdir, f)
for f in os.listdir(zipdir)
if os.path.splitext(f)[1] == ".zip"]
if len(zipfiles) > num:
zipfiles.sort(key=extractTime, reverse=True)
for i in range(num, len(zipfiles)):
os.remove(zipfiles[i])